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120.400=6300x-18x^2-400
We move all terms to the left:
120.400-(6300x-18x^2-400)=0
We add all the numbers together, and all the variables
-(6300x-18x^2-400)+120.4=0
We get rid of parentheses
18x^2-6300x+400+120.4=0
We add all the numbers together, and all the variables
18x^2-6300x+520.4=0
a = 18; b = -6300; c = +520.4;
Δ = b2-4ac
Δ = -63002-4·18·520.4
Δ = 39652531.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6300)-\sqrt{39652531.2}}{2*18}=\frac{6300-\sqrt{39652531.2}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6300)+\sqrt{39652531.2}}{2*18}=\frac{6300+\sqrt{39652531.2}}{36} $
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